An Introduction to Algebraic Geometry and Algebraic Groups - download pdf or read online

By Meinolf Geck

ISBN-10: 019967616X

ISBN-13: 9780199676163

An available textual content introducing algebraic geometries and algebraic teams at complex undergraduate and early graduate point, this e-book develops the language of algebraic geometry from scratch and makes use of it to establish the idea of affine algebraic teams from first principles.

Building at the heritage fabric from algebraic geometry and algebraic teams, the textual content presents an advent to extra complicated and specialized fabric. An instance is the illustration conception of finite teams of Lie type.

The textual content covers the conjugacy of Borel subgroups and maximal tori, the idea of algebraic teams with a BN-pair, an intensive therapy of Frobenius maps on affine kinds and algebraic teams, zeta services and Lefschetz numbers for kinds over finite fields. specialists within the box will get pleasure from a number of the new techniques to classical results.

The textual content makes use of algebraic teams because the major examples, together with labored out examples, instructive routines, in addition to bibliographical and old feedback.

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Extra resources for An Introduction to Algebraic Geometry and Algebraic Groups

Sample text

We claim that ker(α) = (f). Indeed, it is clear that α(f) = 0. Conversely, let g ∈ k[Y1 , . . , Yd+1 ] be such that α(g) = 0, and assume that f does not divide g. 9, there exist F, G ∈ k[Y1 , . . , Yd+1 ] such that 0 = d := Gf + Fg ∈ k[Y1 , . . , Yd ]; note that Yd+1 occurs in some term of f. Then we obtain d(z1 , . . , zd ) = α(Gf + Fg) = 0, contradicting the fact that z1 , . . , zd are algebraically independent. So we have ker(α) = (f) as claimed. On the other hand, the image of α is just R.

Xn ]/I where I ⊆ k[X1 , . . , Xn ] is an ideal. Let M be an A-module, and set n TA,M := (v1 , . . vi = 0 for all f ∈ I , i=1 where Di denotes partial derivative with respect to Xi and the bar denotes the canonical map k[X1 , . . , Xn ] → A. Then, for any v = (v1 , . . vi for f ∈ k[X1 , . . , Xn ]. i=1 The map Φ : TA,M → Derk (A, M ), v → Dv , is an A-module isomorphism. Proof Let R := k[X1 , . . , Xn ] and consider the canonical map ¯ with kernel I. Then we can also regard M as an π : R → A, f → f, R-module via π.

Furthermore, for any invertible matrix A ∈ Mn (k), we have A−1 = det(A)−1 A˜tr , where A˜ is the matrix of cofactors of A; the entries of A˜ are given by the determinants of various submatrices of A of size n − 1. Thus, ι : SLn (k) → SLn (k), A → A−1 , is regular and so SLn (k) is a linear algebraic group, which is called the special linear group. Finally, if k is algebraically closed, then SLn (k) is an irreducible hypersurface with I(SLn (k)) = (det −1). 9, one has to check that det −1 ∈ k[Xij | 1 i, j n] is irreducible.

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An Introduction to Algebraic Geometry and Algebraic Groups by Meinolf Geck


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